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cex: display all the S/R conflicts, not just one per (state, rule)
Before this commit, on
%%
exp
: "if" exp "then" exp
| "if" exp "then" exp "else" exp
| exp "+" exp
| "num"
we used to not display the third counterexample below:
Shift/reduce conflict on token "+":
Example exp "+" exp . "+" exp
First derivation exp ::=[ exp ::=[ exp "+" exp . ] "+" exp ]
Second derivation exp ::=[ exp "+" exp ::=[ exp . "+" exp ] ]
Shift/reduce conflict on token "else":
Example "if" exp "then" "if" exp "then" exp . "else" exp
First derivation exp ::=[ "if" exp "then" exp ::=[ "if" exp "then" exp . ] "else" exp ]
Second derivation exp ::=[ "if" exp "then" exp ::=[ "if" exp "then" exp . "else" exp ] ]
Shift/reduce conflict on token "+":
Example "if" exp "then" exp . "+" exp
First derivation exp ::=[ exp ::=[ "if" exp "then" exp . ] "+" exp ]
Second derivation exp ::=[ "if" exp "then" exp ::=[ exp . "+" exp ] ]
Shift/reduce conflict on token "+":
Example "if" exp "then" exp "else" exp . "+" exp
First derivation exp ::=[ exp ::=[ "if" exp "then" exp "else" exp . ] "+" exp ]
Second derivation exp ::=[ "if" exp "then" exp "else" exp ::=[ exp . "+" exp ] ]
* src/counterexample.c (counterexample_report_state): Don't stop of
the first conflicts.
* tests/conflicts.at, tests/counterexample.at, tests/diagnostics.at,
* tests/report.at: Adjust.
This commit is contained in:
@@ -79,6 +79,11 @@ Shift/reduce conflict on token B:
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First derivation s ::=[ a ::=[ A . ] bc ::=[ B C ] ]
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Second derivation s ::=[ ac ::=[ A ac ::=[ b ::=[ . B ] ] C ] ]
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Shift/reduce conflict on token B:
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Example A A . B B C C
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First derivation s ::=[ a ::=[ A a ::=[ A . ] ] bc ::=[ B bc ::=[ B C ] C ] ]
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Second derivation s ::=[ ac ::=[ A ac ::=[ A ac ::=[ b ::=[ . b ::=[ B B ] ] ] C ] C ] ]
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input.y:6.4: warning: rule useless in parser due to conflicts [-Wother]
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]])
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@@ -328,6 +333,11 @@ Shift/reduce conflict on token B:
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First derivation s ::=[ n ::=[ N a ::=[ A . ] B ] C ]
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Second derivation s ::=[ n ::=[ N b ::=[ A . B C ] ] ]
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Shift/reduce conflict on token B:
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Example N N A . B D C
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First derivation s ::=[ n ::=[ N n ::=[ N a ::=[ A . ] B ] D ] C ]
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Second derivation s ::=[ n ::=[ N n ::=[ N b ::=[ A . B D ] ] C ] ]
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input.y:5.4: warning: rule useless in parser due to conflicts [-Wother]
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]])
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