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cb9f4cb543
The shell grammar does not allow empty statements in then/else part of
an if, but examples/test failed to catch the syntax errors from the
script it ran. So exited with success anyway.
You would expect 'set -e' to suffice, but with bash 3.2 actually it
does not. As a matter of fact, I could find a way to have this behave
properly:
$ cat test.sh
set -e
cleanup ()
{
status=$?
echo "cleanup: $status"
exit $status
}
trap cleanup 0 1 2 13 15
. $1
s=$?
echo "test.sh: $s"
exit $s
$ cat bistro.test
if true; then
fi
$ /bin/sh ./test.sh ./bistro.test
./bistro.test: line 2: syntax error near unexpected token `fi'
cleanup: 0
$ echo $?
0
Remove the set -e (or the trap), and tada, it works... So we have to
deal with the error by hand.
* examples/test ($exit): Replace with...
($status): this.
Preserve the exit status of the test case.
* examples/c/bistromathic/bistromathic.test: Fix syntax error.
This directory contains examples of Bison grammar files, sorted per language.
Several of them come from the documentation, which should be installed together with Bison. The URLs are provided for convenience.
These examples come with a README and a Makefile. Not only can they be used to toy with Bison, they can also be starting points for your own grammars.
Please, be sure to read the C examples before looking at the other languages, as these examples are simpler.